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Question Number 113907 by bemath last updated on 16/Sep/20
∫xcos(x)dx
Answered by bobhans last updated on 16/Sep/20
K=∫xcos(x)dxletx=t2⇒dx=2tdtK=∫2t2costdt=2t2sint+4tcost−4sint+c=2xsin(x)+4xcos(x)−4sin(x)+c=(2x−4)sin(x)+4xcos(x)+c
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