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Question Number 113931 by Rasheed.Sindhi last updated on 16/Sep/20

∣ x ∣=2⇒ x=2 ∨ x=−2 OR ∣ x ∣=2⇒ x=2 ∧ x=−2 ?

$$\mid\:{x}\:\mid=\mathrm{2}\Rightarrow\:{x}=\mathrm{2}\:\vee\:{x}=−\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{OR} \\ $$$$\mid\:{x}\:\mid=\mathrm{2}\Rightarrow\:{x}=\mathrm{2}\:\wedge\:{x}=−\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:? \\ $$

Commented by bemath last updated on 16/Sep/20

or sir. hihihi x = 2 or −2 because ∣x∣ = { ((x ; if x≥0)),((−x; if x< 0)) :}

$${or}\:{sir}.\:{hihihi} \\ $$$${x}\:=\:\mathrm{2}\:{or}\:−\mathrm{2}\: \\ $$$${because}\:\mid{x}\mid\:=\:\begin{cases}{{x}\:;\:{if}\:{x}\geqslant\mathrm{0}}\\{−{x};\:{if}\:{x}<\:\mathrm{0}}\end{cases} \\ $$

Commented by Rasheed.Sindhi last updated on 16/Sep/20

Thanks miss beemath ��

Answered by MJS_new last updated on 16/Sep/20

x=2∧x=−2 is false because a=b∧a=c ⇒ b=c we write x=2∨x=−2 but we should write x=2 xor x=−2 because “∨” excludes only “none of both” a b a∧b a∨b a xor b 1 1 1 1 0 1 0 0 1 1 0 1 0 1 1 0 0 0 0 0 where 1 means true and 0 means false

$${x}=\mathrm{2}\wedge{x}=−\mathrm{2}\:\mathrm{is}\:{false}\:\mathrm{because} \\ $$$${a}={b}\wedge{a}={c}\:\Rightarrow\:{b}={c} \\ $$$$\mathrm{we}\:\mathrm{write}\:{x}=\mathrm{2}\vee{x}=−\mathrm{2}\:\mathrm{but}\:\mathrm{we}\:\mathrm{should}\:\mathrm{write} \\ $$$${x}=\mathrm{2}\:\mathrm{xor}\:{x}=−\mathrm{2}\:\mathrm{because}\:``\vee''\:\mathrm{excludes}\:\mathrm{only} \\ $$$$``\mathrm{none}\:\mathrm{of}\:\mathrm{both}'' \\ $$$${a}\:\:\:\:\:{b}\:\:\:\:\:{a}\wedge{b}\:\:\:\:\:{a}\vee{b}\:\:\:\:\:{a}\:\mathrm{xor}\:{b} \\ $$$$\mathrm{1}\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0} \\ $$$$\mathrm{1}\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1} \\ $$$$\mathrm{0}\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1} \\ $$$$\mathrm{0}\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0} \\ $$$$\mathrm{where}\:\mathrm{1}\:\mathrm{means}\:{true}\:\mathrm{and}\:\mathrm{0}\:\mathrm{means}\:{false} \\ $$

Commented by Rasheed.Sindhi last updated on 16/Sep/20

T_(HNKS ) S_(IR ) MJS for a detailed answer! Felt difference in the forum after your being active!

$$\mathcal{T}_{\mathcal{HNKS}\:} \:\:\mathcal{S}_{\mathcal{IR}\:\:\:} \mathcal{MJS} \\ $$$${for}\:{a}\:{detailed}\:{answer}! \\ $$$${Felt}\:{difference}\:{in}\:{the}\:{forum} \\ $$$${after}\:{your}\:{being}\:{active}! \\ $$

Commented by bemath last updated on 16/Sep/20

super..==

$${super}..== \\ $$

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