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Question Number 113931 by Rasheed.Sindhi last updated on 16/Sep/20

$$\mid x\mid =2\Rightarrow x=2\vee x=-2$$$$OR$$$$\mid x\mid =2\Rightarrow x=2\wedge x=-2$$$$?$$

Commented by bemath last updated on 16/Sep/20

$$orsir.hihihi$$$$x=2or-2$$$$because\mid x\mid =\{\begin{array}{l}x;ifx⩾0\\ -x;ifx<0\end{array}$$

Commented by Rasheed.Sindhi last updated on 16/Sep/20

Thanks miss beemath ��

Answered by MJS_new last updated on 16/Sep/20

$$x=2\wedge x=-2\mathrm{is}false\mathrm{because}$$$$a=b\wedge a=c\Rightarrow b=c$$$$\mathrm{we}\mathrm{write}x=2\vee x=-2\mathrm{but}\mathrm{we}\mathrm{should}\mathrm{write}$$$$x=2\mathrm{xor}x=-2\mathrm{because}‘‘{\vee }^{″}\mathrm{excludes}\mathrm{only}$$$$‘‘\mathrm{none}\mathrm{of}{\mathrm{both}}^{″}$$$$aba\wedge ba\vee ba\mathrm{xor}b$$$$11110$$$$10011$$$$01011$$$$00000$$$$\mathrm{where}1\mathrm{means}true\mathrm{and}0\mathrm{means}false$$

Commented by Rasheed.Sindhi last updated on 16/Sep/20

$${\mathcal{T}}_{\mathcal{HNKS}}{\mathcal{S}}_{\mathcal{IR}}\mathcal{MJS}$$$$foradetailedanswer!$$$$Feltdifferenceintheforum$$$$afteryourbeingactive!$$

Commented by bemath last updated on 16/Sep/20

$$super..==$$

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