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Question Number 11403 by JAZAR last updated on 24/Mar/17

how can demonstred that   cos(2x)−sin(2x)−1=−cos^2 x

$${how}\:{can}\:{demonstred}\:{that}\: \\ $$$${cos}\left(\mathrm{2}{x}\right)−{sin}\left(\mathrm{2}{x}\right)−\mathrm{1}=−{cos}^{\mathrm{2}} {x} \\ $$

Commented by sm3l2996 last updated on 24/Mar/17

I think that equation is not correct  because cos(2π)−sin(2π)−1=0≠−cos^2 (π)

$$\mathrm{I}\:\mathrm{think}\:\mathrm{that}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{not}\:\mathrm{correct} \\ $$$$\mathrm{because}\:\mathrm{cos}\left(\mathrm{2}\pi\right)−\mathrm{sin}\left(\mathrm{2}\pi\right)−\mathrm{1}=\mathrm{0}\neq−\mathrm{cos}^{\mathrm{2}} \left(\pi\right) \\ $$

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