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Question Number 114114 by aurpeyz last updated on 17/Sep/20

$$$$$$\mathrm{A}50\mathrm{g}\mathrm{golf}\mathrm{ball}\mathrm{is}\mathrm{struck}\mathrm{with}\mathrm{a}\mathrm{club}\mathrm{moving}$$$$\mathrm{with}\mathrm{a}\mathrm{velocity}\mathrm{of}22\mathrm{m}/\mathrm{s}\mathrm{after}\mathrm{it}\mathrm{moves}4\mathrm{cm}\mathrm{and}$$$$\mathrm{ball}\mathrm{accelerates}\mathrm{with}\mathrm{a}\mathrm{velocity}\mathrm{of}44\mathrm{m}/\mathrm{s}.$$$$\mathrm{estimate}\mathrm{the}\mathrm{average}\mathrm{force}\mathrm{exerted}\mathrm{by}\mathrm{the}\mathrm{club}$$$$\mathrm{on}\mathrm{the}\mathrm{ball}.$$

Commented by aurpeyz last updated on 17/Sep/20

$$plshelp$$

Answered by Ar Brandon last updated on 17/Sep/20

$${\mathrm{m}}_{\mathrm{b}}=0.05\mathrm{Kg},{\mathrm{u}}_{\mathrm{b}}=0\mathrm{m}/\mathrm{s},{\mathrm{v}}_{\mathrm{b}}=44\mathrm{m}/\mathrm{s},{\mathrm{m}}_{\mathrm{c}}=?,{\mathrm{u}}_{\mathrm{c}}=22\mathrm{m}/\mathrm{s}$$$${\mathrm{v}}_{\mathrm{c}}=0\mathrm{m}/\mathrm{s}.\mathrm{Momentum}\mathrm{is}\mathrm{conserved}$$$$\Rightarrow {\mathrm{m}}_{\mathrm{b}}{\mathrm{u}}_{\mathrm{b}}+{\mathrm{m}}_{\mathrm{c}}{\mathrm{u}}_{\mathrm{c}}={\mathrm{m}}_{\mathrm{b}}{\mathrm{v}}_{\mathrm{b}}+{\mathrm{m}}_{\mathrm{c}}{\mathrm{v}}_{\mathrm{c}}\Rightarrow {22\mathrm{m}}_{\mathrm{c}}=44\times 0.05$$$$\Rightarrow {\mathrm{m}}_{\mathrm{c}}=0.1\mathrm{Kg}$$$$\mathrm{For}\mathrm{club};$$$$\mathrm{v}=0\mathrm{m}/\mathrm{s},\mathrm{a}=?,\mathrm{u}=22\mathrm{m}/\mathrm{s},\mathrm{s}=4\mathrm{cm}=0.04\mathrm{m}$$$$\mathrm{Using}{\mathrm{v}}^2={\mathrm{u}}^2+2\mathrm{as},0={22}^2+2\mathrm{a}\times 0.04\Rightarrow \mathrm{a}=-6050\mathrm{m}/{\mathrm{s}}^2$$$$\Rightarrow \mathrm{F}=\mathrm{ma}=0.1\times 6050=605\mathrm{N}$$

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