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Question Number 114134 by sherzodbek last updated on 17/Sep/20

(m^2 −n^2 +6(n+m)/(m^2 −(6−n)^2 m+n=12

(m2−n2+6(n+m)/(m2−(6−n)2m+n=12

Commented by sherzodbek last updated on 17/Sep/20

yes

Commented by bemath last updated on 17/Sep/20

do you meant ((m^2 −n^2 +6(n+m))/(m^2 −(6−n)^2 )) ? where m+n = 12

doyoumeantm2−n2+6(n+m)m2−(6−n)2?wherem+n=12

Commented by bemath last updated on 17/Sep/20

⇔ ((12(m−n)+72)/((m+6−n)(m+n−6))) = ((12(m−n)+72)/((m−n+6)(6))) =((2(m−n)+12)/(m−n+6)) = ((2(12−n−n)+12)/(12−n−n+6)) = ((36−4n)/(18−2n)) = ((2(18−2n))/(18−2n)) = 2

⇔12(m−n)+72(m+6−n)(m+n−6)=12(m−n)+72(m−n+6)(6)=2(m−n)+12m−n+6=2(12−n−n)+1212−n−n+6=36−4n18−2n=2(18−2n)18−2n=2

Commented by MJS_new last updated on 17/Sep/20

((m^2 −n^2 +6(n+m))/(m^2 −(6−n)^2 ))=((m+n)/(m+n−6))=2

m2−n2+6(n+m)m2−(6−n)2=m+nm+n−6=2

Answered by sherzodbek last updated on 17/Sep/20

Commented by mathmax by abdo last updated on 18/Sep/20

really good for somebody....

reallygoodforsomebody....

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