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Question Number 114212 by mathdave last updated on 17/Sep/20

Answered by mr W last updated on 18/Sep/20

1+2+3+4+5=15 ×  0+2+3+4+5=14 ✓  0+1+3+4+5=13 ×  0+1+2+4+5=12 ✓  0+1+2+3+5=11 ×  0+1+2+3+4=10 ✓    example with digits 0,2,3,4,5:  xyxyx with x=0,2,5 y=3,4 or x=0,3,4 y=2,5  2×2×2×2×1=16 numbers    totally: 3×16=48 numbers

$$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{15}\:× \\ $$$$\mathrm{0}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{14}\:\checkmark \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{13}\:× \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{2}+\mathrm{4}+\mathrm{5}=\mathrm{12}\:\checkmark \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{5}=\mathrm{11}\:× \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}=\mathrm{10}\:\checkmark \\ $$$$ \\ $$$${example}\:{with}\:{digits}\:\mathrm{0},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5}: \\ $$$${xyxyx}\:{with}\:{x}=\mathrm{0},\mathrm{2},\mathrm{5}\:{y}=\mathrm{3},\mathrm{4}\:{or}\:{x}=\mathrm{0},\mathrm{3},\mathrm{4}\:{y}=\mathrm{2},\mathrm{5} \\ $$$$\mathrm{2}×\mathrm{2}×\mathrm{2}×\mathrm{2}×\mathrm{1}=\mathrm{16}\:{numbers} \\ $$$$ \\ $$$${totally}:\:\mathrm{3}×\mathrm{16}=\mathrm{48}\:{numbers} \\ $$

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