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Question Number 114343 by toa last updated on 18/Sep/20

How many ways can we place 5 identical  books and another 6 identical books  on a shelf?

$$\mathrm{How}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{we}\:\mathrm{place}\:\mathrm{5}\:\mathrm{identical} \\ $$$$\mathrm{books}\:\mathrm{and}\:\mathrm{another}\:\mathrm{6}\:\mathrm{identical}\:\mathrm{books} \\ $$$$\mathrm{on}\:\mathrm{a}\:\mathrm{shelf}? \\ $$

Commented by bemath last updated on 18/Sep/20

= ((11!)/(5!.6!))

$$=\:\frac{\mathrm{11}!}{\mathrm{5}!.\mathrm{6}!} \\ $$

Commented by toa last updated on 18/Sep/20

a little bit of explanation sir.  i mean the logic behind the solution.

$$\mathrm{a}\:\mathrm{little}\:\mathrm{bit}\:\mathrm{of}\:\mathrm{explanation}\:\mathrm{sir}. \\ $$$$\mathrm{i}\:\mathrm{mean}\:\mathrm{the}\:\mathrm{logic}\:\mathrm{behind}\:\mathrm{the}\:\mathrm{solution}. \\ $$

Commented by JDamian last updated on 18/Sep/20

Repeated permutations expression

Commented by toa last updated on 18/Sep/20

Thank you sir for the explanation

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