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Question Number 114379 by A8;15: last updated on 18/Sep/20

Commented by A8;15: last updated on 18/Sep/20

please help

Answered by mr W last updated on 19/Sep/20

Commented by mr W last updated on 19/Sep/20

AC=x AE=HF=(√((4+1)^2 −(4−1)^2 ))=4 CE=x−4=CG BG=BC−CG=(√(x^2 +8^2 ))−x+4 BF^2 =7^2 +4^2 =65 BF^2 =1^2 +BG^2 =1+((√(x^2 +8^2 ))−x+4)^2 1+((√(x^2 +8^2 ))−x+4)^2 =65 (√(x^2 +8^2 ))−x+4=8 (√(x^2 +8^2 ))=4+x ⇒x=6

AC=xAE=HF=(4+1)2−(4−1)2=4CE=x−4=CGBG=BC−CG=x2+82−x+4BF2=72+42=65BF2=12+BG2=1+(x2+82−x+4)21+(x2+82−x+4)2=65x2+82−x+4=8x2+82=4+x⇒x=6

Commented by A8;15: last updated on 19/Sep/20

thank you sir!

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