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Question Number 114514 by mohammad17 last updated on 19/Sep/20

Commented by bobhans last updated on 19/Sep/20

(B) u^→ .v^→  = ∣u^→ ∣.∣v^→ ∣ ⇔ cos α=1   α=0°

(B)u.v=u.vcosα=1α=0°

Commented by mohammad17 last updated on 19/Sep/20

wow ! thank you sir

wow!thankyousir

Answered by bobhans last updated on 19/Sep/20

(A) a^→ .b^→  = ∣a^→ ×b^→ ∣   ∣a^→ ∣.∣b^→ ∣.cos α=∣a^→ ∣.∣b^→ ∣.sin α  → tan α=1 ; a=(π/4), ((3π)/4)

(A)a.b=a×ba.b.cosα=∣a.b.sinαtanα=1;a=π4,3π4

Commented by bobhans last updated on 19/Sep/20

gave kudos...

gavekudos...

Commented by mohammad17 last updated on 19/Sep/20

thank you sir can you help me in (B) please

thankyousircanyouhelpmein(B)please

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