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Question Number 114709 by mohammad17 last updated on 20/Sep/20

Commented by mohammad17 last updated on 20/Sep/20

help me sir pleas

$${help}\:{me}\:{sir}\:{pleas} \\ $$

Answered by 1549442205PVT last updated on 20/Sep/20

Choose a,b,d,e)80,70,60,50  We need find δ such that  ∀x:  ∣x−1∣<δ then ∣(√x)−1∣<8(1)  because ∣(√x)−1∣<8⇔−8<(√x)−1<8  ⇐0≤(√x)<9⇐0≤x<81⇐−1≤x−1<80  ⇐∣x−1∣<80  Hence choose δ≤80 then(1) is satisfied

$$\left.\mathrm{Choose}\:\mathrm{a},\mathrm{b},\mathrm{d},\mathrm{e}\right)\mathrm{80},\mathrm{70},\mathrm{60},\mathrm{50} \\ $$$$\mathrm{We}\:\mathrm{need}\:\mathrm{find}\:\delta\:\mathrm{such}\:\mathrm{that} \\ $$$$\forall\mathrm{x}:\:\:\mid\mathrm{x}−\mathrm{1}\mid<\delta\:\mathrm{then}\:\mid\sqrt{\mathrm{x}}−\mathrm{1}\mid<\mathrm{8}\left(\mathrm{1}\right) \\ $$$$\mathrm{because}\:\mid\sqrt{\mathrm{x}}−\mathrm{1}\mid<\mathrm{8}\Leftrightarrow−\mathrm{8}<\sqrt{\mathrm{x}}−\mathrm{1}<\mathrm{8} \\ $$$$\Leftarrow\mathrm{0}\leqslant\sqrt{\mathrm{x}}<\mathrm{9}\Leftarrow\mathrm{0}\leqslant\mathrm{x}<\mathrm{81}\Leftarrow−\mathrm{1}\leqslant\mathrm{x}−\mathrm{1}<\mathrm{80} \\ $$$$\Leftarrow\mid\mathrm{x}−\mathrm{1}\mid<\mathrm{80} \\ $$$$\mathrm{Hence}\:\mathrm{choose}\:\delta\leqslant\mathrm{80}\:\mathrm{then}\left(\mathrm{1}\right)\:\mathrm{is}\:\mathrm{satisfied} \\ $$

Commented by mohammad17 last updated on 20/Sep/20

thank you sir can you help me in otber question

$${thank}\:{you}\:{sir}\:{can}\:{you}\:{help}\:{me}\:{in}\:{otber}\:{question} \\ $$

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