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Question Number 115237 by nisaketto last updated on 24/Sep/20

	Answered by nimnim last updated on 24/Sep/20

	$A = area of regular hexagon - area of circle$ $= \frac{3 \sqrt{3}}{2} a^{2} - π r^{2} = (\frac{3 \times 1.732}{2} \times 6 \times 6) - (\frac{22}{7} \times 2 \times 2)$ $= 93.528 - 0.785 = 92 . {77 cm}^{2}$ $t h e q u e s t i o n s a i d r a d i u s i s 2 c m w h i l e t h e$ $f i g u r e r e p r e s e n t r a d i u s i s 4.2 c m$ $O R (\frac{3 \sqrt{3}}{2} \times 6 \times 6) - (\frac{22}{7} \times 4.2 \times 4.2)$ $= 93.528 - 55.55$ $= 38.088 \approx 38.09 {cm}^{2}$
	Answered by EvoneAkashi last updated on 24/Sep/20

	$T h e a r e a o f t h e h e x a g o n i s \frac{3 \sqrt{3}}{2} \times 6^{2} = 54 \sqrt{3} {c m}^{2} .$ $T h e a r e a o f t h e c i r c l e i s π \times 2^{2} = 4 π {c m}^{2},$ $S o t h e a r e a f i n d e d i s (54 \sqrt{3} - 4 π) {c m}^{2} .$
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