Question and Answers Forum

All Questions      Topic List

Logarithms Questions

Previous in All Question      Next in All Question      

Previous in Logarithms      Next in Logarithms      

Question Number 115246 by bemath last updated on 24/Sep/20

    5^((x+1)^2 )  + 625 ≤ 5^(x^2 +2)  + 5^(2x+3)

$$\:\:\:\:\mathrm{5}^{\left({x}+\mathrm{1}\right)^{\mathrm{2}} } \:+\:\mathrm{625}\:\leqslant\:\mathrm{5}^{{x}^{\mathrm{2}} +\mathrm{2}} \:+\:\mathrm{5}^{\mathrm{2}{x}+\mathrm{3}} \\ $$

Commented by bobhans last updated on 24/Sep/20

let 5^x^2   = r ∧ 5^(2x)  = s

$${let}\:\mathrm{5}^{{x}^{\mathrm{2}} } \:=\:{r}\:\wedge\:\mathrm{5}^{\mathrm{2}{x}} \:=\:{s} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com