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Question Number 115364 by Bird last updated on 25/Sep/20

calculate ∫∫_([0,1]^2 )   (√(xy))(x^2 +y^2 )dxdy

calculate[0,1]2xy(x2+y2)dxdy

Answered by Olaf last updated on 25/Sep/20

∫∫_([0,1]^2 ) ((√y)x^(5/2) +y^(5/2) (√x))dxdy  = ∫_0 ^1 [(2/7)(√y)x^(7/2) +(2/3)y^(5/2) x^(3/2) ]_0 ^1 dy  = ∫_0 ^1 ((2/7)(√y)+(2/3)y^(5/2) )dy  = [(2/7)×(2/3)y^(3/2) +(2/3)×(2/7)y^(7/2) ]_0 ^1   = (8/(21))

[0,1]2(yx5/2+y5/2x)dxdy=01[27yx7/2+23y5/2x3/2]01dy=01(27y+23y5/2)dy=[27×23y3/2+23×27y7/2]01=821

Commented by mathmax by abdo last updated on 25/Sep/20

thank you sir

thankyousir

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