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Question Number 115364 by Bird last updated on 25/Sep/20
calculate∫∫[0,1]2xy(x2+y2)dxdy
Answered by Olaf last updated on 25/Sep/20
∫∫[0,1]2(yx5/2+y5/2x)dxdy=∫01[27yx7/2+23y5/2x3/2]01dy=∫01(27y+23y5/2)dy=[27×23y3/2+23×27y7/2]01=821
Commented by mathmax by abdo last updated on 25/Sep/20
thankyousir
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