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Question Number 115661 by bemath last updated on 27/Sep/20
(1)∫sin(x)dx(2)∫cos(x)dx(3)∫tan(x)dx
Answered by Dwaipayan Shikari last updated on 27/Sep/20
∫sin(x)dxx=t2⇒1=2tdtdx2∫tsin(t)dt−2tcos(t)+2∫cost−2tcos(t)+2sint+C=−2xcos(x)+2sin(x)+C
∫cos(x)dx2∫tcos(t)2tsint−2∫sint2tsint+2cost+C2xsin(x)+2cos(x)+C
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