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Question Number 115830 by mohammad17 last updated on 28/Sep/20
createthedifferentionequationfromx2+y2+2ax+2by+c=0
Commented by bemath last updated on 29/Sep/20
⇒x2+2ax+a2+y2+2by=a2+b2−c⇒(x+a)2+(y+b)2=a2+b2−c⇒ddx[(x+a)2+(y+b)2]=02(x+a)+2(y+b)y′=0⇒y′=−(x+a)(y+b)
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