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Question Number 115882 by Khalmohmmad last updated on 29/Sep/20

Answered by PRITHWISH SEN 2 last updated on 29/Sep/20

$$\mathrm{sgn}(\mathrm{x}+1)=1\mathrm{when}\mathrm{x}>-1$$$$\mathrm{sgn}(\mathrm{x}+1)=0\mathrm{when}\mathrm{x}+1=0$$$$\mathrm{sgn}(\mathrm{x}+1)=-1\mathrm{when}\mathrm{x}<-1$$$$\because \mathrm{denominator}\ne 0\therefore \mathrm{sgn}(\mathrm{x}+1)\ne 1$$$$\therefore \mathrm{domain}\mathrm{x}\in (-\mathrm{\infty },-1]$$

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