2x+3y+4z=1 ⇒min((1/x)+(1/y)+(1/z))


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Question Number 115888 by Fikret last updated on 29/Sep/20

$2 x + 3 y + 4 z = 1 \Rightarrow m i n (\frac{1}{x} + \frac{1}{y} + \frac{1}{z})$
Commented by mr W last updated on 29/Sep/20

$l e t 3 y + 4 z \to 1$ $\Rightarrow 2 x + 1 \to 1$ $\Rightarrow x \to 0$ $(\frac{1}{x} + \frac{1}{y} + \frac{1}{z}) \to \infty o r - \infty$ $\Rightarrow n o m a x i m u m o r m i n i m u m!$
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