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Question Number 115898 by bemath last updated on 29/Sep/20
$${If}\:{Mike}\:{has}\:\mathrm{10}\:{blocks}\:{numbered} \\ $$$${from}\:\mathrm{1}\:{through}\:{to}\:\mathrm{10}\:.\:{What}\:{is}\:{the} \\ $$$${probability}\:{that}\:{he}\:{didn}'{t}\:{choose} \\ $$$${a}\:{block}\:{number}\:\mathrm{7}? \\ $$
Answered by TANMAY PANACEA last updated on 29/Sep/20
$${i}\:{think}.. \\ $$$${choosing}\:{block}\:{no}\:\mathrm{7}\:{is}=\frac{\mathrm{1}}{\mathrm{10}} \\ $$$${not}\:{choosing}\:{block}\:{no}\mathrm{7}\:{is}\:=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{10}}=\frac{\mathrm{9}}{\mathrm{10}} \\ $$
Commented by bemath last updated on 29/Sep/20
$${yes}\:{sir}.\:{thank}\:{you} \\ $$