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Question Number 115960 by Fikret last updated on 29/Sep/20
f2(x)=f(2x)+2f(x)−2f(1)=3⇒f(6)=?
Commented by prakash jain last updated on 29/Sep/20
powerconvertedintolinearf(x)=eax+be2ax+2beax+b2=e2ax+b+2eax+2b−2b=1f(x)=eax+1f(1)=3⇒3=ea−1⇒a=ln2f(x)=2x+1f(6)=26+1=65
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