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Question Number 11600 by tawa last updated on 28/Mar/17

$$\mathrm{A}\mathrm{number}\mathrm{is}\mathrm{selected}\mathrm{at}\mathrm{random}\mathrm{from}\mathrm{the}\mathrm{integers}1\mathrm{to}100\mathrm{exclusive},$$$$\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{chance}\mathrm{of}\mathrm{choosing}\mathrm{at}\mathrm{random}\mathrm{a}\mathrm{two}\mathrm{digit}\mathrm{number}\mathrm{which}\mathrm{is}$$$$\left(\mathrm{a}\right)\mathrm{Divisible}\mathrm{by}4$$$$\left(\mathrm{b}\right)\mathrm{The}\mathrm{multiple}\mathrm{of}5$$

Answered by mrW1 last updated on 29/Mar/17

$$numberstoselect:1,2,3,...,100\Rightarrow 101pieces$$$$$$$$twodigitnumbersdivisibleby4:$$$$12,16,...,96\Rightarrow 22pieces$$$$$$$$multipleof5:$$$$5,10,...,95\Rightarrow 19pieces$$$$$$$$\left(a\right):\frac{22}{101}=21.8\mathrm{\%}$$$$\left(b\right):\frac{19}{101}=18.8\mathrm{\%}$$

Commented by tawa last updated on 29/Mar/17

$$\mathrm{Wow},\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Commented by tawa last updated on 29/Mar/17

$$\mathrm{Sir},\mathrm{the}\mathrm{exclussive},\mathrm{i}\mathrm{thought}\mathrm{it}\mathrm{mean}1\mathrm{and}100\mathrm{will}\mathrm{not}\mathrm{be}\mathrm{there}$$

Commented by mrW1 last updated on 29/Mar/17

$$then\left(a\right)=\frac{22}{99}and\left(b\right)=\frac{19}{99}$$

Commented by tawa last updated on 29/Mar/17

$$\mathrm{Thank}\mathrm{you}\mathrm{sir}.$$

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