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Question Number 116051 by Hassen_Timol last updated on 30/Sep/20

$$\mathrm{What}\mathrm{is}\mathrm{the}\mathrm{modulus}\mathrm{and}\mathrm{the}\mathrm{argument}$$$$\mathrm{of}1+i(1+\sqrt{2})?$$

Answered by Dwaipayan Shikari last updated on 30/Sep/20

$$\mathrm{z}=1+\mathrm{i}(1+\sqrt{2})$$$$\mid \mathrm{z}\mid =\sqrt{1+1+2+2\sqrt{2}}=\sqrt{4+2\sqrt{2}}$$$$\arg \left(\mathrm{z}\right)={\tan }^{-1}(\sqrt{2}+1)$$

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