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Question Number 116163 by harckinwunmy last updated on 01/Oct/20
Ineedageneralruleforfactorising1)an+bn2)an−bnwhennisevenandwhennisodd.
Answered by 1549442205PVT last updated on 02/Oct/20
Ineedageneralruleforfactorising1)an+bn2)an−bnwhennisevenandwhennisodd.i)whenniseven:n=2kwehave1)a2k+b2k=(ak+bk)2−2akbk(ak+2akbk+bk)(ak−2akbk+bk)2)a2k−b2k=(ak+bk)(ak−bk)=(ak+bk)(a−b)(ak−1+ak−2b+ak−3b2+...+bk−1)ii)Whennisodd:n=2k+1wehave1)a2k+1+b2k+1=(a+b)(a2k−a2k−1b+a2k−2b2−...+b2k)2)a2k+1−b2k+1=(a−b)(a2k+a2k−1b+...+ab2k−1+b2k)
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