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Question Number 116184 by ZiYangLee last updated on 01/Oct/20
Howmany6−digitspositiveintegerswhichareformedbythedigits1to9aresuchthateachofthedigitsinthenumberappearsatleasttwice?[Forinstance:121233,122221,777777andetc.]
Answered by mr W last updated on 01/Oct/20
wehavefollowingcases:AABBCC⇒C39×6!2!2!2!=7560AAABBB⇒C29×6!3!3!=720AAAABB⇒C29×6!4!2!=540AAAAAA⇒C19=9totally7560+720+540+9=8829
Commented by ZiYangLee last updated on 02/Oct/20
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