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Question Number 116524 by abdullahquwatan last updated on 04/Oct/20

if α+β+γ=180°  prove:  sin α+sin β+sin γ+sin (π/3) < 4 sin (π/3)

$$\mathrm{if}\:\alpha+\beta+\gamma=\mathrm{180}° \\ $$ $$\mathrm{prove}: \\ $$ $$\mathrm{sin}\:\alpha+\mathrm{sin}\:\beta+\mathrm{sin}\:\gamma+\mathrm{sin}\:\frac{\pi}{\mathrm{3}}\:<\:\mathrm{4}\:\mathrm{sin}\:\frac{\pi}{\mathrm{3}} \\ $$

Commented byTANMAY PANACEA last updated on 04/Oct/20

solved but could not upload image

$${solved}\:{but}\:{could}\:{not}\:{upload}\:{image} \\ $$

Answered by TANMAY PANACEA last updated on 04/Oct/20

Commented byabdullahquwatan last updated on 05/Oct/20

thank you sir

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

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