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Question Number 116588 by bemath last updated on 05/Oct/20
limx→04x2cosecx(1−cosx)=?
Answered by bobhans last updated on 05/Oct/20
limx→04x.sinx2(1−1−2sin2(x2))=limx→04x.sinx2(1−(1−2(x24)2))=limx→0[2x2(x24)]=8
Answered by Dwaipayan Shikari last updated on 05/Oct/20
limx→04x22(1−cosx)=2x21−cosx(1+cosx)=2.2x22sin2x2=8
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