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Question Number 116595 by ZiYangLee last updated on 05/Oct/20
If(1−2x+3x2)10=a0+a1x+a2x2+...+a20x20findthevalueofa1+a2+...+a20
Answered by mr W last updated on 05/Oct/20
putx=0:(1−0+0)10=a0+a10+a20+...+a200⇒a0=1putx=1:(1−2+3)10=a0+a11+a21+...+a201⇒210=a0+a1+a2+...+a20⇒a1+a2+...+a20=210−a0=210−1
Commented by ZiYangLee last updated on 05/Oct/20
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