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Question Number 116611 by gaminghanzo12 last updated on 05/Oct/20

Commented by Dwaipayan Shikari last updated on 05/Oct/20

Q 116516

Q116516

Answered by TANMAY PANACEA last updated on 05/Oct/20

(a/(b+c))+1+(b/(a+c))+1+(c/(a+b))+1−3 (a+b+c)((1/(b+c))+(1/(a+c))+(1/(a+b)))−3 7×(7/(10))−3=((49−30)/(10))=((19)/(10))

ab+c+1+ba+c+1+ca+b+1−3(a+b+c)(1b+c+1a+c+1a+b)−37×710−3=49−3010=1910

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