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Question Number 116845 by mohammad17 last updated on 07/Oct/20

Commented by mohammad17 last updated on 07/Oct/20

$$helpmesir$$

Answered by TANMAY PANACEA last updated on 07/Oct/20

$$stlineAB\frac{x-2}{6-2}=\frac{y-4}{8-4}\to \frac{x-2}{1}=\frac{y-4}{1}$$$$directionratio(1,1)$$$$r=2i+4j+\alpha (i+j)$$$$l_{1}is{r}_1=6i+4j+\lambda (i+j)$$$$\frac{x-6}{1}=\frac{y-4}{1}directionratioof{l}_{1}is(1,1)$$$$soAB\parallel to{l}_1$$$$l_{2}eqnis\frac{x-6}{6-4}=\frac{z-0}{0-2}$$$$vectoreqn{l}_{2}isr=6i+0k+\lambda (2i-2k)$$$$or\frac{x-4}{6-4}=\frac{z-2}{0-2}\to r=4i+2k+\lambda (2i-2k)$$$$$$

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