prove that 7×8=7+8=78


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Question Number 116941 by Her_Majesty last updated on 08/Oct/20

$p r o v e t h a t 7 \times 8 = 7 + 8 = 78$
Commented by MJS_new last updated on 08/Oct/20
$one possible “proof” { ((1=e^(2πi) )),((1=e^(4πi) )) :} ⇔ 2πi=4πi ⇔ 2=4 ⇔ ⇔ 1×2=2×2 ⇔ 1=2 ⇔ 1+n=2+n i.e. n=1 ⇒ 1+1=2+1 ⇔ 2=3 but 1=2 ⇔ ⇔ 1+1=2+1=2+2=4 ... tbis leads to (1) m=n ∀ m, n ∈N (we can easily expand this to C) ⇒ 7×8=p∈N∧7+8=q∈N and because of (1) ⇒ 7×8=7+8=k∈N but 78=h∈N and again using (1) ⇒ k=h ⇒ 7×8=7+8=78 q. e. d.$
$one possible ‘ ‘ {proof}^{″}$ ${\begin{cases} 1 = e^{2 π i} \\ 1 = e^{4 π i} \end{cases} \Leftrightarrow 2 π i = 4 π i \Leftrightarrow 2 = 4 \Leftrightarrow$ $\Leftrightarrow 1 \times 2 = 2 \times 2 \Leftrightarrow 1 = 2 \Leftrightarrow 1 + n = 2 + n$ $i . e . n = 1 \Rightarrow 1 + 1 = 2 + 1 \Leftrightarrow 2 = 3 but 1 = 2 \Leftrightarrow$ $\Leftrightarrow 1 + 1 = 2 + 1 = 2 + 2 = 4 . . .$ $tbis leads to$ $(1) m = n \forall m, n \in N$ $(we can easily expand this to C)$ $\Rightarrow 7 \times 8 = p \in N \land 7 + 8 = q \in N and because of (1)$ $\Rightarrow 7 \times 8 = 7 + 8 = k \in N$ $but 78 = h \in N and again using (1)$ $\Rightarrow k = h$ $\Rightarrow 7 \times 8 = 7 + 8 = 78$ $q . e . d .$
Commented by Her_Majesty last updated on 08/Oct/20

$g r e a t!$
Commented by bemath last updated on 08/Oct/20
all calculators in the world are wrong, because the calculator calculates the result 56
Commented by Her_Majesty last updated on 08/Oct/20

$y e s! {i t}^{'} s a w o r l d w i d e c o n s p i r a c y o f t h e$ $c a l c u l a t o r i n d u s t r i e s t o g e t h e r w i t h t h e$ $u n i v e r s i t i e s . . . t h e y a l l w o u l d l o s e b i l l i o n s$ $i f t h e t r u t h w a s r e v e i l e d!$
Commented by MJS_new last updated on 08/Oct/20

$the calculator says 7 \times 8 = 56 but since I$ $showed that all natural numbers are one$ $this makes no difference . at least the$ $calculator must show a result, so why not$ $show ‘ ‘ 56^{″} ?$
Commented by bemath last updated on 08/Oct/20
all the teachers in this world are wrong. because it teaches students 5x6 = 30 not 56
Commented by MJS_new last updated on 08/Oct/20

$yes . everything is wrong because$ $u = v \forall u, v \in C$ $\Rightarrow π = e = i = \sqrt{37} = γ = . . . = 42$
Commented by I want to learn more last updated on 08/Oct/20

$Hahahahaha$
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