Prove ((cos(A−B))/(sin(A+B)))=((1+tan Atan B)/(tan Atan B))


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Question Number 116975 by ZiYangLee last updated on 08/Oct/20

$Prove \frac{\cos (A - B)}{\sin (A + B)} = \frac{1 + \tan A \tan B}{\tan A \tan B}$
Commented by Dwaipayan Shikari last updated on 08/Oct/20

$\frac{c o s (A - B)}{s i n (A + B)} = \frac{c o s A c o s B + s i n A s i n B}{s i n A c o s B + c o s A s i n B} = \frac{1 + t a n A t a n B}{t a n A + t a n B}$
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