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Question Number 116976 by bobhans last updated on 08/Oct/20
usetheformulaP=Iekt,wherePisresultingpopulation,Iistheinitialpopulationandtismeasuredinhours.Abacterialculturehasaninitialpopulationof10,000.Ifitsdeclinesto5000in6hours,whatwillitbeattheendof8hours?(a)1985(b)3969(c)2500(d)4353
Answered by bobhans last updated on 08/Oct/20
⇒5000=10,000e6k⇒500010,000=e6k⇒12=e6k;6k=−ln2k=−ln26=−0.115525wewantcomputeP=10,000e8kP=10,000e−8×0.115525=3969
Answered by Rio Michael last updated on 08/Oct/20
iwillsayP(t)=P0ektjustbecauseamusetowritingitthisway.soP0=10,000bac,P(6)=5000bac⇒5000=10,000e6k⇒12=e6kln(12)=6kork=−ln26hence,P(t)=10000e−ln26twhent=8,P(8)=10,000e−4ln23=3969answer=(b)
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