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Question Number 117243 by A8;15: last updated on 10/Oct/20

Commented by A8;15: last updated on 10/Oct/20

please help sir

Answered by Olaf last updated on 10/Oct/20

  u_n  = x+((n+1)/u_(n+1) )  u_0  = x+(1/u_1 ) = x+(1/(x+(2/u_2 ))) = x+(1/(x+(2/(x+(3/(u_3 ...))))))  C = u_0  = x

$$ \\ $$$${u}_{{n}} \:=\:{x}+\frac{{n}+\mathrm{1}}{{u}_{{n}+\mathrm{1}} } \\ $$$${u}_{\mathrm{0}} \:=\:{x}+\frac{\mathrm{1}}{{u}_{\mathrm{1}} }\:=\:{x}+\frac{\mathrm{1}}{{x}+\frac{\mathrm{2}}{{u}_{\mathrm{2}} }}\:=\:{x}+\frac{\mathrm{1}}{{x}+\frac{\mathrm{2}}{{x}+\frac{\mathrm{3}}{{u}_{\mathrm{3}} ...}}} \\ $$$$\mathrm{C}\:=\:{u}_{\mathrm{0}} \:=\:{x} \\ $$

Commented by A8;15: last updated on 10/Oct/20

the answer is C=x ?

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