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Question Number 117577 by ZiYangLee last updated on 12/Oct/20

$$\mathrm{If}f\left(x\right),g\left(x\right)\mathrm{and}h\left(x\right)\mathrm{are}\mathrm{three}\mathrm{functions},$$$$\mathrm{where}f\left(x\right)=2x^5-8x^2+1,f(x-3)=g(3x-2)$$$$\mathrm{and}g(3x+1)=h(x+3),\mathrm{show}h\left(x\right)=f(x-5).$$

Answered by Olaf last updated on 12/Oct/20

$$h\left(x\right)=g(3(x-3)+1)=g(3(x-2)-2)$$$$=f((x-2)-3)=f(x-5)$$

Commented by ZiYangLee last updated on 12/Oct/20

$$\mathrm{hmmm}..$$

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