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Question Number 117608 by TANMAY PANACEA last updated on 12/Oct/20

$$solve$$$$\frac{d^{2}y}{{dt}^2}+w^{2}x=0$$

Answered by Dwaipayan Shikari last updated on 12/Oct/20

$$\frac{d}{dt}\left(\frac{dy}{dt}\right)=-w^{2}x$$$$\frac{da}{dt}=-w^{2}xa=\frac{dy}{dt}$$$$a=-w^{2}xt+C$$$$\frac{dy}{dt}=-w^{2}xt+C\Rightarrow y=-\frac{w^2}{2}{xt}^2+Ct+A$$

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