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Question Number 117654 by jeewanbee640 last updated on 13/Oct/20

Commented by prakash jain last updated on 13/Oct/20

(ii) does not have period 2π  f(1)=1  f(2π+1)=8π+4≠f(1)

$$\left({ii}\right)\:\mathrm{does}\:\mathrm{not}\:\mathrm{have}\:\mathrm{period}\:\mathrm{2}\pi \\ $$$${f}\left(\mathrm{1}\right)=\mathrm{1} \\ $$$${f}\left(\mathrm{2}\pi+\mathrm{1}\right)=\mathrm{8}\pi+\mathrm{4}\neq{f}\left(\mathrm{1}\right) \\ $$

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