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Question Number 117800 by Khalmohmmad last updated on 13/Oct/20

Answered by mr W last updated on 13/Oct/20

$$\log 2=\log \frac{6}{3}=\log 6-\log 3=a-b$$$$\log 25=\log {\left(\frac{10}{2}\right)}^2=2(\log 10-\log 2)$$$$=2(1-a+b)$$

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