1)((√3)−1)((√3)+1)=(√3)×(√3)−(√3)−1 =3−(√3)−1 =2−(√3) 2)(2x+(√3))(2x−(√3))=(2x)^2 −2x(√3)+2x(√3)−3 =4x^2 −3


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Question Number 117828 by redouaneee last updated on 13/Oct/20

$1) (\sqrt{3} - 1) (\sqrt{3} + 1) = \sqrt{3} \times \sqrt{3} - \sqrt{3} - 1$ $= 3 - \sqrt{3} - 1$ $= 2 - \sqrt{3}$ $2) (2 x + \sqrt{3}) (2 x - \sqrt{3}) = {(2 x)}^{2} - 2 x \sqrt{3} + 2 x \sqrt{3} - 3$ $= 4 x^{2} - 3$
	Answered by MJS_new last updated on 13/Oct/20

	$(\sqrt{3} - 1) (\sqrt{3} + 1) = \sqrt{3} \times \sqrt{3} - \sqrt{3} + \sqrt{3} - 1 = 3 - 1 = 2$ $(a - b) (a + b) = a^{2} - b^{2}$
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