how many four digit numbers can be formed with the digits 0 1 2 3 4 5 6 7 8 9?


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Question Number 117866 by aurpeyz last updated on 14/Oct/20

$h o w m a n y f o u r d i g i t n u m b e r s c a n b e$ $f o r m e d w i t h t h e d i g i t s 0 1 2 3 4 5 6 7 8$ $9 ?$
Commented by mr W last updated on 14/Oct/20

$w i t h r e p e t i t i o n :$ $1000, 1001, . . ., 9999$ $\Rightarrow 9999 - 999 = 9000 n u m b e r s$
Commented by mhmoud last updated on 14/Oct/20
good
Commented by mr W last updated on 14/Oct/20

$w i t h o u t r e p e t i t i o n :$ $\frac{9}{10} \times P_{4}^{10} = 4536 n u m b e r s$ $o r$ $P_{4}^{10} - P_{3}^{9} = 4536 n u m b e r s$
	Answered by 1549442205PVT last updated on 14/Oct/20

	$10^{4} - ∣ \overset{―}{0 abc} ∣= 10^{4} - 10^{3} = 10000 - 1000$ $= 9000$
	Answered by bobhans last updated on 14/Oct/20

	$9 \times 10^{3} = 9, 000$
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