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Question Number 117912 by A8;15: last updated on 14/Oct/20

Commented by A8;15: last updated on 14/Oct/20

help please

Answered by Lordose last updated on 14/Oct/20

$$$$$$$$$${\int }_0^1\frac{{\left({\mathrm{Li}}_2\left(\mathrm{x}\right)\right)}^2}{\mathrm{x}}+{\int }_0^1\frac{{\mathrm{Li}}_2\left(\mathrm{x}\right)}{\mathrm{x}}$$$${\int }_0^1\frac{{\left({\mathrm{Li}}_2\left(\mathrm{x}\right)\right)}^2}{\mathrm{x}}+\mid {\mathrm{Li}}_3\left(\mathrm{x}\right){\mid }_0^1$$$$\mathrm{\Omega }+\zeta \left(3\right)$$$$\mathrm{\Omega }={\int }_0^1\frac{{\mathrm{Li}}_2^2\left(\mathrm{x}\right)}{\mathrm{x}}$$

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