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Question Number 118088 by bobhans last updated on 15/Oct/20

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{\mathrm{x}.\sqrt{{\mathrm{x}}^2+1}.\sqrt[3]{{\mathrm{x}}^3+1}}{{(2\mathrm{x}+1)}^3}=?$$

Answered by bemath last updated on 15/Oct/20

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{\mathrm{x}.\sqrt{{\mathrm{x}}^2}.\sqrt[3]{{\mathrm{x}}^3}}{{8\mathrm{x}}^3}=\underset{x\to \mathrm{\infty }}{\lim }\frac{{\mathrm{x}}^3}{{8\mathrm{x}}^3}=\frac{1}{8}$$

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