All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 118094 by bemath last updated on 15/Oct/20
∫dxsecx+2=?
Answered by Dwaipayan Shikari last updated on 15/Oct/20
12∫2cosxdx2cosx+1=12∫1−12cosx+1dx=x2−∫12−2t21+t2+1.11+t2t=tanx2=x2−∫13−t2dt=x2+123log(t−3t+3)=x2+123log(tanx2−3tanx2+3)+C
Commented by bemath last updated on 15/Oct/20
weirstrasssubstitutionsantuy...
Terms of Service
Privacy Policy
Contact: info@tinkutara.com