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Question Number 118133 by andilizhaa last updated on 15/Oct/20

$$2.\mathrm{Turunan}\mathrm{pertama}\mathrm{dari}\mathrm{f}\left(\mathrm{x}\right)={5\mathrm{x}}^4+\mathrm{x}\sqrt{\mathrm{x}}+\frac{6}{\sqrt{\times }}-\sin \mathrm{x}-2\cos \mathrm{x}+5adalah...$$$$\mathrm{a}.{\mathrm{f}}^1\left(\mathrm{x}\right)={20\mathrm{x}}^3+\frac{3}{2}\sqrt{\mathrm{x}}+\frac{6}{\times \sqrt{\times }}+\cos \mathrm{x}-2\sin \mathrm{x}$$$$\mathrm{b}.{\mathrm{f}}^1\left(\mathrm{x}\right)={20\mathrm{x}}^3+\frac{3}{2}\sqrt{\mathrm{x}}-\frac{3}{\mathrm{x}\sqrt{\mathrm{x}}}-\cos \mathrm{x}+2\sin \mathrm{x}$$$$\mathrm{c}.{\mathrm{f}}^1\left(\mathrm{x}\right)={20\mathrm{x}}^3+\frac{3}{2}\sqrt{\mathrm{x}}-\frac{1}{\mathrm{x}\sqrt{\mathrm{x}}}-\cos \mathrm{x}+2\sin \mathrm{x}$$$$\mathrm{d}.{\mathrm{f}}^1\left(\mathrm{x}\right)={20\mathrm{x}}^3+\frac{2}{3}\sqrt{\mathrm{x}}-\frac{3}{\mathrm{x}\sqrt{\mathrm{x}}}+\cos \mathrm{x}+2\sin \mathrm{x}$$$$\mathrm{e}.{\mathrm{f}}^1\left(\mathrm{x}\right)={20\mathrm{x}}^3+\frac{3}{2}\sqrt{\mathrm{x}}-\frac{1}{\mathrm{x}\sqrt{\mathrm{x}}}+\cos \mathrm{x}+2\sin \mathrm{x}$$

Commented by 1549442205PVT last updated on 15/Oct/20

$$\mathrm{It}\mathrm{is}\mathrm{Indonexia}\mathrm{language}\mathrm{that}\mathrm{means}$$$$‘‘\mathrm{the}\mathrm{first}\mathrm{derivative}\mathrm{of}\mathrm{f}\left(\mathrm{x}\right)={5\mathrm{x}}^4+\mathrm{x}\sqrt{\mathrm{x}}$$$$+\frac{6}{\sqrt{\mathrm{x}}}-\mathrm{sinx}-2\mathrm{cosx}+5{\mathrm{is}}^{″}$$

Commented by andilizhaa last updated on 15/Oct/20

$$ijustwrite$$

Commented by Lordose last updated on 15/Oct/20

$$\mathrm{Translated}$$$$\mathrm{First}\mathrm{derivative}$$

Commented by Lordose last updated on 15/Oct/20

B benar

Commented by andilizhaa last updated on 15/Oct/20

$$thankyouall$$

Answered by 1549442205PVT last updated on 15/Oct/20

$$\mathrm{Choose}\mathrm{B}$$

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