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Question Number 118156 by bemath last updated on 15/Oct/20

(1−x^2 )y′′−8xy′−12y=0

$$\left(\mathrm{1}−{x}^{\mathrm{2}} \right){y}''−\mathrm{8}{xy}'−\mathrm{12}{y}=\mathrm{0} \\ $$

Commented by TANMAY PANACEA last updated on 15/Oct/20

still searching the way to reach goal

$${still}\:{searching}\:{the}\:{way}\:{to}\:{reach}\:{goal} \\ $$

Commented by SANOGO last updated on 30/Aug/21

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