Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 118165 by andilizhaa last updated on 15/Oct/20

Commented by Dwaipayan Shikari last updated on 15/Oct/20

$$Translate$$

Answered by Olaf last updated on 15/Oct/20

$$\mathrm{Mean}\stackrel{\mathrm{\_}}{x}=\frac{1}{8}(8+5+2+6+7+10+6+4)$$$$\stackrel{\mathrm{\_}}{x}=\frac{48}{8}=6$$$$\mathrm{Average}\mathrm{deviation}\mathrm{of}\mathrm{data}:$$$$\frac{1}{8}(2+1+4+0+1+4+0+2)=\frac{14}{8}=\frac{7}{4}$$

Answered by Dwaipayan Shikari last updated on 15/Oct/20

$$\stackrel{-}{X}=\frac{8+5+2+6+7+10+6+4}{8}=6$$$$MeanDeviation=\frac{1}{n}\underset{r=1}{\sum ^n}\mid X_r-\stackrel{-}{X}\mid \left(Generally\right)$$$$SoMeandeviation$$$$\frac{1}{8}(2+1+4+1+4+2)=\frac{7}{4}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com