Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 118180 by mathocean1 last updated on 15/Oct/20

show that if n is odd , n(n^2 +3) is even.

$${show}\:{that}\:{if}\:{n}\:{is}\:{odd}\:,\:{n}\left({n}^{\mathrm{2}} +\mathrm{3}\right)\:{is}\:{even}. \\ $$

Answered by floor(10²Eta[1]) last updated on 15/Oct/20

if n is odd⇒n=2k+1, k∈Z  (2k+1)((2k+1)^2 +3)  =(2k+1)(4k^2 +4k+4)  =4(2k+1)(k^2 +k+1)=even because  it′s a multiple of 2

$$\mathrm{if}\:\mathrm{n}\:\mathrm{is}\:\mathrm{odd}\Rightarrow\mathrm{n}=\mathrm{2k}+\mathrm{1},\:\mathrm{k}\in\mathbb{Z} \\ $$$$\left(\mathrm{2k}+\mathrm{1}\right)\left(\left(\mathrm{2k}+\mathrm{1}\right)^{\mathrm{2}} +\mathrm{3}\right) \\ $$$$=\left(\mathrm{2k}+\mathrm{1}\right)\left(\mathrm{4k}^{\mathrm{2}} +\mathrm{4k}+\mathrm{4}\right) \\ $$$$=\mathrm{4}\left(\mathrm{2k}+\mathrm{1}\right)\left(\mathrm{k}^{\mathrm{2}} +\mathrm{k}+\mathrm{1}\right)=\mathrm{even}\:\mathrm{because} \\ $$$$\mathrm{it}'\mathrm{s}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{2} \\ $$$$ \\ $$

Commented by mathocean1 last updated on 15/Oct/20

thanks

$${thanks} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com