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Question Number 118228 by bobhans last updated on 16/Oct/20

$$\underset{x\to 0}{\lim }\frac{\sum _{\mathrm{r}=1}^{10}{(\mathrm{x}+\mathrm{r})}^{2020}}{({\mathrm{x}}^{1008}+1)({3\mathrm{x}}^{1012}+1)}=?$$

Answered by MJS_new last updated on 16/Oct/20

$$\mathrm{simply}\mathrm{put}x=0$$$$\mathrm{answer}\mathrm{is}\underset{r=1}{\sum ^{10}}{r}^{2020}\mathrm{which}\mathrm{cannot}\mathrm{be}\mathrm{calculated}$$

Commented by bobhans last updated on 16/Oct/20

$$yes$$

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