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Question Number 118270 by bramlexs22 last updated on 16/Oct/20
∫xax(1−a)1−xdx?
Commented by Dwaipayan Shikari last updated on 16/Oct/20
(1−a)∫x(a(1−a))x1−alog(a1−a)x(a1−a)x−1−alog(a1−a)∫(a1−a)x1−alog(a1−a)x(a1−a)x−1−alog2(a1−a).(a1−a)x+C(1−alog(a1−a)(a1−a)x).(x+1log(a1−a))+C
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