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Question Number 118304 by mnjuly1970 last updated on 16/Oct/20

$$$$$$...\underset{\text{blacktrinagledown}}{\stackrel{\text{blacktrinagledown}}{⧫}}\mathcal{A}dvancedcalculus\underset{\text{blacktrinagledown}}{\stackrel{\text{blacktrinagledown}}{⧫}}...$$$$provethat::$$$$$$$$\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{1}{3^n{n}^3}\stackrel{???}{=}\frac{7}{8}\zeta \left(3\right)+\frac{1}{6}{ln}^3\left(2\right)-\frac{{\pi }^2}{12}ln\left(2\right)✓$$$$...\mathrm{♠}\mathcal{M}.\mathcal{N}.\mathcal{J}uly1970\mathrm{♠}...$$$$.\mathcal{G}oodluck.$$$$$$

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