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Question Number 118366 by andilizhaa last updated on 17/Oct/20

4. Turunan fungsi f(x)=^5 (√((10x^2 −4)^8   ))  adalah f^1 (x). Nilai f^1 (1)=...  a. 1  b. 8  c. 14  d. 16  e. 20

$$\mathrm{4}.\:\mathrm{Turunan}\:\mathrm{fungsi}\:\mathrm{f}\left(\mathrm{x}\right)=^{\mathrm{5}} \sqrt{\left(\mathrm{10x}^{\mathrm{2}} −\mathrm{4}\right)^{\mathrm{8}} \:\:} \\ $$$$\mathrm{adalah}\:\mathrm{f}^{\mathrm{1}} \left(\mathrm{x}\right).\:\mathrm{Nilai}\:\mathrm{f}^{\mathrm{1}} \left(\mathrm{1}\right)=... \\ $$$${a}.\:\mathrm{1} \\ $$$${b}.\:\mathrm{8} \\ $$$${c}.\:\mathrm{14} \\ $$$$\mathrm{d}.\:\mathrm{16} \\ $$$$\mathrm{e}.\:\mathrm{20} \\ $$

Commented by bramlexs22 last updated on 17/Oct/20

translate in english

$${translate}\:{in}\:{english} \\ $$

Commented by bramlexs22 last updated on 17/Oct/20

do you meant f^1 (x) equal to (dy/dx) ?

$${do}\:{you}\:{meant}\:{f}^{\mathrm{1}} \left({x}\right)\:{equal}\:{to}\:\frac{{dy}}{{dx}}\:? \\ $$$$ \\ $$

Commented by andilizhaa last updated on 17/Oct/20

where the dy and dx?

$${where}\:{the}\:{dy}\:{and}\:{dx}? \\ $$

Commented by prakash jain last updated on 17/Oct/20

I think all options are wrong  f^1 (x)=(df/dx)=(8/5)(10x^2 −4)^(3/5) ×20x  x=1  f^1 (1)=32×(6)^(3/5)

$$\mathrm{I}\:\mathrm{think}\:\mathrm{all}\:\mathrm{options}\:\mathrm{are}\:\mathrm{wrong} \\ $$$${f}^{\mathrm{1}} \left({x}\right)=\frac{{df}}{{dx}}=\frac{\mathrm{8}}{\mathrm{5}}\left(\mathrm{10}{x}^{\mathrm{2}} −\mathrm{4}\right)^{\mathrm{3}/\mathrm{5}} ×\mathrm{20}{x} \\ $$$${x}=\mathrm{1} \\ $$$${f}^{\mathrm{1}} \left(\mathrm{1}\right)=\mathrm{32}×\left(\mathrm{6}\right)^{\mathrm{3}/\mathrm{5}} \\ $$

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