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Question Number 118455 by Ravin1989 last updated on 17/Oct/20

Commented by benjo_mathlover last updated on 17/Oct/20

$$\left(4\right)\mid 3A\mid =3^3\times \mid A\mid =27\times 8=216$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$9)d=\mid \frac{-2\times 0+6\times 0-3\times 0+7}{\sqrt{{(-2)}^2+{\left(6\right)}^2+{(-3)}^2}}\mid =\frac{7}{\sqrt{49}}=1$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$6)y={lnx}^2-{lne}^2\to y=2lnx-2$$$$\frac{dy}{dx}=\frac{2}{x}\to \frac{d^{2}y}{{dx}^2}=\frac{-2}{x^2}$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$5\int x^2{e}^{x^3}dx$$$$\frac{1}{3}\int e^{x^3}d\left(x^3\right)=\frac{1}{3}\times e^{x^3}+c$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$7)p\left(A\right)samplespace\{4,5,6\}p\left(A\right)=\frac{3}{6}$$$$p\left(B\right)samplespace\{1,2,3,4\}p\left(B\right)=\frac{4}{6}$$$$p(A\cap B)samplespace\left\{4\right\}p(A\cap B)=\frac{1}{6}$$$$p(A\cup B)=p\left(A\right)+p\left(B\right)-p(A\cap B)=\frac{3}{6}+\frac{4}{6}-\frac{1}{6}=1$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$3)\mathit{p}\mathit{l}\mathit{s}\mathit{c}\mathit{h}\mathit{e}\mathit{c}\mathit{k}...$$$$\mathit{t}\mathit{h}\mathit{e}\mathit{r}\mathit{e}\mathit{i}\mathit{s}\mathit{o}\mathit{n}\mathit{e}\mathit{q}\mathit{u}\mathit{e}\mathit{e}\mathit{n}\mathit{o}\mathit{f}\mathit{s}\mathit{p}\mathit{a}\mathit{d}\mathit{e}$$$$\mathit{s}\mathit{o}\mathit{p}\mathit{r}\mathit{o}\mathit{b}\mathit{a}\mathit{b}\mathit{l}\mathit{i}\mathit{t}\mathit{y}=\frac{1}{52}$$$$othersirsplscomment$$

Commented by prakash jain last updated on 17/Oct/20

$$Ithinkconditionalprobability$$$$shouldbeused.$$$$\mathrm{P}(A\cap B)=P(A\mid B)P\left(B\right)$$$$AQueenofspade$$$$BQueen$$$$giventhatitisqueentheprobibility$$$$thatitisqueenofspadeis\frac{1}{4}$$$$pleasecheckandcomment$$

Answered by TANMAY PANACEA last updated on 17/Oct/20

$$\mid E\overrightarrow{A}\mid =\mid EC\mid$$$$E\overrightarrow{C}=-E\overrightarrow{A}$$$$E\overrightarrow{D}=-E\overrightarrow{B}$$$$E\overrightarrow{A}+E\overrightarrow{B}+E\overrightarrow{C}+E\overrightarrow{D}=0$$

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